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[b]Prisms[/b][br]
volume = area [multiply] length [length can be height if vertical]
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[b]Arcs and Sectors[/b][br]
sector area = ([theta] [divide] 360) [pi]r[squared] [r = radius][br]
(arcs) [theta] [divide] 360 [multiply] [pi]d [d = diameter]
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[b]Cylinders[/b][br]
volume = [pi]r[squared] [multiply] h [h = height; r = radius][br]
surface area = 2[pi]r[squared] + (2[pi]r [multiply] h) [r = radius; h = height]
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[b]Spheres and Hemispheres[/b][br]
sphere volume ---> (4 [divide] 3) [multiply] [pi]r[cubed][br]
sphere surface area ---> 4 [multiply] [pi]r[squared]
[br][br]
hemisphere volume ---> (2 [divide] 3) [multiply] [pi]r[cubed][br]
hemisphere surface area ---> (2 [multiply] [pi]r[squared]) + [pi]r[squared]
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[b]Square Based Pyramids[/b][br]
volume = (base area [multiply] height) [divide] 3[br]
surface area = 2bs + b[squared] [b = base length; s = slanted height]
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[b]Cones[/b][br]
volume = (base area [multiply] height) [divide] 3 [its a circle based pyramid][br]
surface area = ([pi] [multiply] radius [multiply] slanted height) + [pi]r[squared]
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[b]Frustums[/b][br]
-Frustums consist of 1 large cone, minus a smaller one[br]
-The smaller cone's radius is proportional to the large cone's radius[br]
-Therefore the smaller cone's height also follows the same ratio and vice versa[br]
[br]
-To find the volume of the [b]frustum[/b], calculate the volume of the large cone and find its difference with the small cone[br]
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[b]Cuboids[/b][br]
[i]a = height, b = width, c = depth(z axis)[/i][br]
volume = a[multiply] b[multiply] c[br]
surface area = 2(ab + ac + bc)
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